Question

Build a dynamic array of 10 ints on the heap. Assign a value of 10* index number to each element.

Display the array.

Wrap the following in a 5 count loop:

Generate a random number. Even – add 1 element to the array. Odd –subject 1 element from the array.

Print what happened.

Print the entire loop again.

Answer 1

#include<stdlib.h>
#include<iostream>

//main function
int main()
{   
//declaring dynamic array
int *a = new int[10];
int index = 9;
// assigning value to array
for(int i=0; i<=index; i++){
a[i] = i*10;
}
for(int i=0; i<=index; i++){
std::cout<<a[i]<<"\t";
}
std::cout<<std::endl;
  
//looping 5 times
for(int i=0; i<5; i++)
{
//generating random number
int num = rand();
  
//if random number is even
if(num%2 == 0)
{
index++;
a[index] = index*10;

for(int i=0; i<=index; i++)
std::cout<<a[i]<<"\t";
std::cout<<"\n 1 Element is added to array"<<std::endl;
}
else
{
//if random number is add

--index;

  for(int i=0; i<=index; i++)
std::cout<<a[i]<<"\t";
std::cout<<"\n 1 Element is Subtracted from array "<<std::endl;
}
}
std::cout<<std::endl;

//printing value of array
std::cout<<" After 5 iteration array is: "<<std::endl;
for(int i=0; i<=index; i++){
std::cout<<a[i]<<"\t";
}
}