In a double‑slit interference experiment, the wavelength is ?=532 nm , the slit separation is ?=0.190...
In a double‑slit interference experiment, the wavelength is ?=532 nm , the slit separation is ?=0.190 mm , and the screen is ?=50.0 cm away from the slits. What is the linear distance Δ? between the seventh order maximum and the fifth order maximum on the screen?
Homework Answers
condition for constructive interference is
d sin theta = m lamda
for small angles sin theta = tan theta = y/L
d ( y/D) = m lamda
for m = 7
y7= m lamda D/ d
= 7(532* 10^-9) (50* 10^-2)/0.190 * 10^-3 m
=9.8 * 10^-3 m
for m = 5
y5= m lamda D/ d
= 5(532* 10^-9) (50* 10^-2)/0.190 * 10^-3 m
=7 * 10^-3 m
del x = y7 - y5 = 9.8 * 10^-3 m -7* 10^-3 m = 2.8 * 10^-3 m = 2.8 mm
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