if the mean of a random sample of size 400 is used to estimate the mean of an infinite population with a standard deviation of 60, the probability is 0.95 that the error is less than
|
5.88. |
||
|
117.6. |
||
|
1.96. |
||
|
3.92. |
Solution :
Given that,
Z
/2
= 1.96
Margin of error = E = Z
/2*
(
/
n)
= 1.96 * (60 /
400)
= 5.88
The probability is 0.95 that the error is less than 5.88
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