Assume Z is standard normal. Find the following values
(A) P(−0.43 ≤ Z ≤ 0.43)
(B) P(Z ≥ 1.54)
Solution:
A)
P(-0.43 < z < 0.43)
= P(z < -0.43) - P(z < 0.43)
= 0.6664 - 0.3336 Using standard normal table,
Probability = 0.3328
B)
P(Z ≥ 1.54) = 1 - P(Z < 1.54 )
= 1 - 0.9352 Using standard normal table,
Probability = 0.0618
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