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A roller coaster car travels around a vertical loop. At the top of the loop, where...

A roller coaster car travels around a vertical loop. At the top of the loop, where it is upside down, it is moving at a speed of 10 m/s. Given that the loop has a radius of 8.0 m,

a) What is the value of the car’s centripetal acceleration at that instant in time?

b) A 55 kg passenger is in the car. Draw a free‐body diagram showing all the forces acting on the passenger.

c) What is the magnitude of the normal force of the car acting on the passenger?

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Answer #1

a) centripetal acceleration = v^2/r

centripetal acceleration = 10^2/8

centripetal acceleration = 12.5 m/s^2

b)

c) magnitude of normal force

magnitude of normal force = mv^2/r - mg

magnitude of normal force = 55 * (12.5 - 9.8)

magnitude of normal force = 149 N

the magnitude of normal force is 149 N

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