Question

IN PYTHON ONLY !! Design (pseudocode) and implement (source code) a program (name it Occurrences) to determine whether two two-dimensional arrays are equivalent or not. Two arrays are equivalent if they contain the same values in any order. The program main method defines two two-dimensional array of size 3-by-3 of type integer, and prompts the user to enter integer values to initialize the arrays.

- The main method calls method isEquivalent()that takes two two-dimensional arrays of integer and returns true (boolean value) if the arrays contain the same values in any order, otherwise it returns false.

- Hint: use a sort method from Lab 14 in developing the solution for this problem.

- Document your code and properly label the input prompts and the outputs as shown below.

Sample run 1:

Array A:

    1   2   3

    4   5   6

    7   8 9

   

Array B:

    1   2   3

    6   5   4

    7   8   9

Judgment: The arrays are equivalent.

Sample run 2:

Array A:

    1   1   1

    1   5   6

    1   1   1

   Array B:

    1   1   1

    1   6   6

    1   1   1

Judgment: The arrays are not equivalent.

Answer 1

Thanks for the question, here is the complete code in python, comments added to all important line so that you can understand whats going on

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# function to check if two arrays has all the numbers in common
def isEquivalent(matrix1,matrix2):
    # create a single dimensional list to store all the 9 numbers for matrix 1
    numbers_one=[]
    for row in matrix1:
        for num in row:
            numbers_one.append(num)
    # once all numbers are added we sort them in ascending order
    numbers_one.sort()
    # create a single dimensional list to store all the 9 numbers for matrix 2
    numbers_two=[]
    for row in matrix2:
        for num in row:
            numbers_two.append(num)
    # once all numbers are added we sort them in ascending order
    numbers_two.sort()
    # first check if both the list has 9 elements
    # if the count is not 9 we return False
    if len(numbers_one) is not 9 or len(numbers_two) is not 9:
        return False
    # for each index we compare both numbers in both the list
    # if for an index the number dont match we immediately return False
    for i in range(len(numbers_one)):
        if numbers_one[i] is not numbers_two[i]:
            return False
    # if all check passes we finally return True
    return True

m1=[[1,2,3],[4,5,6],[7,8,9]]
m2=[[1,7,8],[2,6,3],[4,5,11]]
if (isEquivalent(m1,m2)):
    print('Judgement: The arrays are equivalent.')
else:
    print('Judgement: The arrays are not equivalent.')

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thanks !