describe and sketch the plot of Temperature vs. Time for the freezing point of Lauric Acid.
why does the plot appear as it does (there should be three important "sections" in the plot, explain what is happening in each)?
describe and sketch the plot of Temperature vs. Time for the freezing point of Lauric Acid....
describe and sketch the plot of Temperature vs. Time for the evaporation of alcohol. why does the plot appear as it does (explain any increases/decreases in temperature)?
DATA AND CALCULATIONS Mass of lauric acid Mass of benzoic acid Freezing temperature of pure lauric acid Freezing point of the benzoic acid-lauric acid mixture Freezing temperature depression, At 38-1c Molality, m molkg Moles of benzoic acid mol Molecular weight of benzoic acid (experimental) g/mo Molecular weight of benzoic acid (accepted) g/mol Percent error
mass of lauric acid = 8.001g mass of benzoic acid = 1.001g freezing temperature of pure lauric acid = 43.3 c freezing point of the benzoic acid- lauric acid mix = 38.3 c 1- calculate the molality(m), in mol/kg, using the formula delta(t) = Kf * m. the Kf value for lauric acid is 3.9 C*Kg/mol 2- Calculate moles of benzoic acid solute, using the molality and the mass in (kg) of lauric acid solvent. 3- calculate the experimental molecular...
No water was added, the only substances in the flask was the
lauric acid and the unknown. we were finding the freezing point.
heated the glass to 60c everything dissolved took it out of hot
bath and recorded temp drop which stopped at 39.44c
Unknown # Identify the unknown: Data: nknen Mass of Lauric Acid 9427 kat Et 31.442 43,2 Freezing Point of Lauric Acid Mass of Unknown .922 Freezing Point of Mixture Results and Discussion: (SHOW WORK FOR CREDIT)...
(V) (8 points) What is the freezing point temperature for a solution of 1.221 g of benzoic acid (C&HsCOOH) in 3 8.000 g of lauric acid? For lauric acid, CHs(CH2)1oCOOH, the normal freezing point is 43.2°C, and Kr value is 3.9 °C/m. 5
Colligative Properties: Freezing Point Depression Lauris acid is added to a test tube and heated. The test tube is placed in water to freeze the lauric acid. After measuring the temperature, an unknown is added. The lauric acid and unknown are heated to a liquid and placed in cold water(Part B). In doing part B of this experiment, Group 1 removes the thermometer and stirring wire to add the unknown, and wipes them off, losing 0.25 g of lauric acid....
CHM 112 Determination of Molar Mass by Freezing Point Depression Report Sheet and Data Analysis DATA TABLE Mass of lauric acid (g) 8.003 Mass of benzoic acid (g) 1.005 Freezing temperature of pure lauric acid (°C) 42.4 Freezing point of the benzoic acid-lauric acid mixture (°C) 38.7 Discuss possible sources of error in this experiment and how those errors would affect the final calculated molar mass. This is an open ended question and a thorough answer is expected. You should...
For each of the velocity vs. time graphs below, sketch possible
corresponding position vs. time and acceleration vs. time graphs.
To the right of the graph, briefly describe the motion of the
object and why the graphs you drew are consistent with the velocity
graph. Where is the object at time t = 0 in each case?
Explain.
please complete everything
:)
PRE-LAB If you were to plot temperature (C) vs. time (minutes) for the following scenario, what would the general profile look like? What important information can be gleaned from your plot? 1) Solute "blue" is dissolved in a beaker of water at room temperature. 2) Room temperature is 22°C 3) 4) Solute "blue" takes about 3 minutes to dissolve. Upon dissolving the beaker warms up...to about 27°C. 5) The beaker containing the solution is then placed...
1) a) For the position vs. time graph shown below, sketch the velocity vs. time and acceleration vs. time graphs corresponding to the motion. (5 pts each) Beside the position and acceleration graphs, describe the motion of the object and explain why you drew the graph the way you did. (10 pts) 25 pts total