What is the mass of calcium phosphate that can be prepared from 1.78 g of NaPO4?...
What is the mass of calcium phosphate that can be prepared from 1.78 g of NaPO4?
Na3PO4? Na3PO4(aq) + Ca(OH)2 (aq) -> Ca3(PO4) (S) + NaOH (aq)
Homework Answers
Balanced equation for this reaction is,
2Na3PO4 + 3Ca(OH)2 -------> Ca3(PO4)2 + 6NaOH
2 moles of Na3PO4 gives 1 mole of Ca3PO4.
Molar mass of Na3PO4 = 163.94 g/mol
Moles of Na3PO4 = 1.78/163.94
= 0.0109 moles
Moles of Ca3PO4 formed = 0.0109/2
= 0.00545 moles
Molar mass of Ca3PO4 = 310.174 g/mol
Mass of Ca3PO4 formed = 310.174 g/mol × 0.00545
= 1.69 grams
Answer = 1.69 g
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What is the mass of calcium phosphate that can be prepared from
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