Use Hooke's Law for this (F = - k s ): Where F is the spring's...
Use Hooke's Law for this (F = - k s ): Where F is the spring's restoring force; k is the spring constant; and s is the stretch. The negative sign means the spring's restoring force is opposite the stretch direction. You have a plot from weight [N] versus stretch [m]. The data forms a linear trend y = 3.662 * x + 1.67. How much will the spring stretch if 51.7 grams is hung on the spring? Answer in centimeters with three significant figures or N/A if not enough information is given to answer. When you calculate your ansswer, don't use the negative sign in the Hooke's Law formula. Just know that the negative sign simply denotes the force direction is opposite the stretch (or compression)
Homework Answers
s Law for this (F--ks): Where F is the spring's restoring force; k is the spring...
s Law for this (F--ks): Where F is the spring's restoring force; k is the spring constant; and s is the stretch. The negative sign means the spring's restoring force is opposite the stretch direction. You have a plot from weight IN] versus stretch [m). The data forms a linear trend y 3.662x+1,67. How much will the spring stretch if 51.7 grams is hung on the spring? Answer in centimeters with three significant figures or N/A if not enough information...
To understand the use of Hooke's law for a spring. Hooke's law states that the restoring...
To understand the use of Hooke's law for a spring. Hooke's law states that the restoring force F⃗ on a spring when it has been stretched or compressed is proportional to the displacement x⃗ of the spring from its equilibrium position. The equilibrium position is the position at which the spring is neither stretched nor compressed. Recall that F⃗ ∝x⃗ means that F⃗ is equal to a constant times x⃗ . For a spring, the proportionality constant is called the spring constant and denoted...
1. According to Hooke's law, the force exerted by a spring is proportional to the amount...
1. According to Hooke's law, the force exerted by a spring is proportional to the amount of stretch (or change in length Ax) and is given by F = -KAX, where the minus sign indicates it is a restoring force. If a force of 120 N acts on a mass 250 g attached to a spring of constant K = 54.55 x 103 N/m. Calculate the following: The change in length Ax The angular frequency (w) The frequency (f) The...
1. According to Hooke's law, the force exerted by a spring is proportional to the amount...
1. According to Hooke's law, the force exerted by a spring is proportional to the amount of stretch (or change in length Ax) and is given by F = -KAx, where the minus sign indicates it is a restoring force. If a force of 120 N acts on a mass 250 g attached to a spring of constant K = 54.55 x 10 N/m. Calculate the following: The change in length Ax The angular frequency (w) The frequency (f) The...
3) Consider Hooke's Law: The force required to keep a spring in a compressed or stretched position x units from the spring's equilibrium position is F(x)-kr Calculate the work required, in jo...
3) Consider Hooke's Law: The force required to keep a spring in a compressed or stretched position x units from the spring's equilibrium position is F(x)-kr Calculate the work required, in joules, to stretch a spring 0.4 meters beyond its equilibrium position for each of the following scenarios. a) The spring requires 50 Newtons of force to hold it 0.1 m from its equilibrium position. b) The spring requires 2 Joules of work to stretch the spring 0.1 meter from...
A spring is found to not obey Hooke's law. It exerts a restoring force F(x) =-ax-...
A spring is found to not obey Hooke's law. It exerts a restoring force F(x) =-ax- 2 N if it stretched or compressed, where α = 60 N/m and β 18.0 Nm2/3. The mass of the spring is negligible. (a) Calculate the work function W(x) for the spring. Let U=0 when x=0. (b) An object of mass 0.900 kg on a horizontal surface is attached to this spring. The surface provides a friction force that is dependent on distance Fr(x)2x2...
Only Parts d, e and f Hooke's Law represents a linear restoring force where an elastic...
Only Parts d, e and f Hooke's Law represents a linear restoring force where an elastic system is displaced from equilibrium. In an experiment a rubber band and a spring were placed in a vertical position and a series of having Masses were attached to the free end. a) Does the rubber band used exhibit Hooke's Law behavior? Why or why not? b) Does the spring used exhibit Hooke's Law behavior ? Why or why not? c) Simple Harmonic Motion...
When a 2.00-kg object is hung vertically on a certain light spring described by Hooke's law,...
When a 2.00-kg object is hung vertically on a certain light spring described by Hooke's law, the spring stretches 2.78 cm. (a) What is the force constant of the spring? N/m (b) If the 2.00-kg object is removed, how far will the spring stretch if a 1.00-kg block is hung on it? cm (c) How much work must an external agent do to stretch the same spring 9.00 cm from its unstretched position?
(1 point) Finding the work done in stretching or compressing a spring. Hooke's Law for Springs....
(1 point) Finding the work done in stretching or compressing a spring. Hooke's Law for Springs. According to Hooke's law, the force required to compress or stretch a spring from an equilibrium position is given by F(x) = kx, for some constant k. The value of k (measured in force units per unit length) depends on the physical characteristics of the spring. The constant k is called the spring constant and is always positive. Part 1. Suppose that it takes...
PHY 3460 Hooke's Law and Elastic Potential Energy Questions When applying a 37.5 N force on...
PHY 3460 Hooke's Law and Elastic Potential Energy Questions When applying a 37.5 N force on a spring it compresses 15.0 cm. Calculate the spring 2) A spring (k 1.22 N/m) is hanging vertically. An unknown mass is hung from the spring 3) A 15.0 kg mass is hung from a spring causing it to stretch 0.25 m, find the spring constant. constant of the spring. causing it to stretch 57.3 mm. How large is the unknown mass? Then, another...
s Law for this (F--ks): Where F is the spring's restoring force; k is the spring constant; and s is the stretch. The negative sign means the spring's restoring force is opposite the stretch direction. You have a plot from weight IN] versus stretch [m). The data forms a linear trend y 3.662x+1,67. How much will the spring stretch if 51.7 grams is hung on the spring? Answer in centimeters with three significant figures or N/A if not enough information...
1. According to Hooke's law, the force exerted by a spring is proportional to the amount of stretch (or change in length Ax) and is given by F = -KAX, where the minus sign indicates it is a restoring force. If a force of 120 N acts on a mass 250 g attached to a spring of constant K = 54.55 x 103 N/m. Calculate the following: The change in length Ax The angular frequency (w) The frequency (f) The...
1. According to Hooke's law, the force exerted by a spring is proportional to the amount of stretch (or change in length Ax) and is given by F = -KAx, where the minus sign indicates it is a restoring force. If a force of 120 N acts on a mass 250 g attached to a spring of constant K = 54.55 x 10 N/m. Calculate the following: The change in length Ax The angular frequency (w) The frequency (f) The...
3) Consider Hooke's Law: The force required to keep a spring in a compressed or stretched position x units from the spring's equilibrium position is F(x)-kr Calculate the work required, in joules, to stretch a spring 0.4 meters beyond its equilibrium position for each of the following scenarios. a) The spring requires 50 Newtons of force to hold it 0.1 m from its equilibrium position. b) The spring requires 2 Joules of work to stretch the spring 0.1 meter from...
A spring is found to not obey Hooke's law. It exerts a restoring force F(x) =-ax- 2 N if it stretched or compressed, where α = 60 N/m and β 18.0 Nm2/3. The mass of the spring is negligible. (a) Calculate the work function W(x) for the spring. Let U=0 when x=0. (b) An object of mass 0.900 kg on a horizontal surface is attached to this spring. The surface provides a friction force that is dependent on distance Fr(x)2x2...
(1 point) Finding the work done in stretching or compressing a spring. Hooke's Law for Springs. According to Hooke's law, the force required to compress or stretch a spring from an equilibrium position is given by F(x) = kx, for some constant k. The value of k (measured in force units per unit length) depends on the physical characteristics of the spring. The constant k is called the spring constant and is always positive. Part 1. Suppose that it takes...
PHY 3460 Hooke's Law and Elastic Potential Energy Questions When applying a 37.5 N force on a spring it compresses 15.0 cm. Calculate the spring 2) A spring (k 1.22 N/m) is hanging vertically. An unknown mass is hung from the spring 3) A 15.0 kg mass is hung from a spring causing it to stretch 0.25 m, find the spring constant. constant of the spring. causing it to stretch 57.3 mm. How large is the unknown mass? Then, another...
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