The time to complete a simple haircut is normally distributed with a mean of 25 minutes...
The time to complete a simple haircut is normally distributed with a mean of 25 minutes and a standard deviation of 4 minutes. What percent of customers require less than 32 minutes for a simple haircut?
a. 95.99%
b. 97.72%
c. 4.01%
d. 45.99%
Homework Answers
Solution :
Given that,
mean = 
= 25
standard deviation = 
= 4
P(X<32 ) = P[(X-
) /
< (32-25) / 4]
= P(z <1.75 )
Using z table
=0.9599
answer=95.99%
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