A(g) + 2B(g) → C(g) + D(g) If you initially start with 1.00 atm of both...

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A(g) + 2B(g) → C(g) + D(g) If you initially start with 1.00 atm of both...

A(g) + 2B(g) → C(g) + D(g) If you initially start with 1.00 atm of both A and B and find that at equilibrium 0.227 atm of C is present, what is the value of Kp for the reaction at the temperature the reaction was run?

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Answer #1

K_p= 0.224

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