Question

The length of salmon that goes up a particular river for spawning can be assumed to be normally distributed with expected length μ = 90 cm and standard deviation σ = 10 cm. The lengths of different salmon are independent.

a) Calculate the probability of a salmon being over 100 cm. Find that length one which is so in only 1% of salmon is longer than one cm. Salmon fishermen in this river have a seasonal quota of 5 salmon. Hanna is eagerly salmon- fisherman and fisherman until she has filled the seasonal quota. Calculate the probability of 6 p.m. the average length of the 5 salmon is over 100 cm. I a larger watercourse it is for salmon tribes, tribe ONE and tribe B . For the tribe ONE is the expected length μ ONE = 90 and the standard deviation σ ONE = 10, lord of tribe B is μ B = 96 and σ B = 8. The lengths are as before independent and normally distributed. It is further known that 70% of the salmon in the watercourse is from stem ONE , men 30% are from tribe B .

b) Calculate the probability that a salmon from the watercourse is over 100 cm. Calculate the probability of a salmon from the tribe ONE is longer than a salmon from tribe B

Answer 1

solution :

a.

b.

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