A relaxed spring of length 0.17 m stands vertically on the floor; its stiffness is 1460...
A relaxed spring of length 0.17 m stands vertically on the floor; its stiffness is 1460 N/m. You release a block of mass 0.6 kg from rest, with the bottom of the block 0.4 m above the floor and straight above the spring. How long is the spring when the block comes momentarily to rest on the compressed spring?
Homework Answers
Free length, L = 0.17 m
Using law of conservation of energy,
0.5 kx^2 = 0.5 mgh
0.5 x 1460 x x^2 = 0.6 x 9.8 x (0.23 + x)
730 x^2 - 5.88 x - 1.35 = 0
X = 0.047 m
Spring length = 0.17 - 0.047 = 0.123 m
Comment in case any doubt please rate my answer ...
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