Question

A golfer rips a tee shot from an elevated driving range tee-off such that the ball...

A golfer rips a tee shot from an elevated driving range tee-off such that the ball leaves horizontally. The ball lands exactly at the 51.7 meter marker, and was shot from the upper level (5.3 meters above the ground). How long was the ball in the air?

And how fast did the ball leave the tee?

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Answer #1

time it takes to reach ground

h = 0.5gt^2

5.3 = 4.9 t^2

t = 1.04 s

motion along horizontal

51.7 = v * t

v = 49.711 m/s

=====

b)

t = 1.04 s

=====

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