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If the lifetime of a particle when it is at rest is 28% of the observed...

If the lifetime of a particle when it is at rest is 28% of the observed lifetime of the particle, how fast is the particle moving?
____________ ×c

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Answer #1

Here,

as rest life time = 0.28 * observed life time

let the speed of the particle is v

Now,

using the time dilation equation

t = t0/sqrt(1 - (v/c)^2)

1/0.28 = 1/sqrt(1 - (v/c)^2)

solving for v

v = 0.96c

the speed of particle is 0.96c

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