The fridge manufacturer claims the average daily electricity consumption of one energy efficient model is 0.5...
The fridge manufacturer claims the average daily electricity consumption of one energy efficient model is 0.5 kW.h, the standard deviation of the daily electricity consumption is 0.16 kW.h. For one random sample of 45 fridges, Find the probability that the sample average daily electricity consumption is greater than 0.55 kW.h.
1.(5 pts) Given a random sample 45 fridges of this model, the average daily electricity consumption of this sample is 0.52 kW.h, calculate 99% two-sided confidence interval for the true average daily electricity consumption.
2.(5 pts) find the sample size nn such that the 99% two-sided confidence interval is at most 0.1.
Only solve 1 &2 please
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The fridge manufacturer claims the average daily electricity
consumption of one energy efficient model is 0.5...
1- The fridge manufacturer claims the average daily electricity consumption of one energy efficient model is...
1- The fridge manufacturer claims the average daily electricity consumption of one energy efficient model is 0.5 kW.h, the standard deviation of the daily electricity consumption is 0.16 kW.h. For one random sample of 45 fridges, Find the probability that the sample average daily electricity consumption is greater than 0.55 kW.h. 2- Given a random sample 45 fridges of this model, the average daily electricity consumption of this sample is 0.52 kW.h, calculate 99% two-sided confidence interval for the true...
9. (10 pts.) A manufacturer of light bulbs claims that the average lifespan of their light...
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[6-34] The manufacturer of a new fiberglass tire claims that its average life will be at...
[6-34] The manufacturer of a new fiberglass tire claims that its average life will be at least 40,000 miles. To verify this claim, sample of 15 tires are tested. Sample mean was 41.1 (in 1000 miles), and sample standard deviation was 2.50. Assuming the measurements were random sample from a Normal distribution, calculate 95% one-sided confidence interval for true mean tire life. Choose lower-bound or upper-bound, whichever is appropriate. (Round to 2 decimals.) Your Answer: Answer
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[6-34] The manufacturer of a new fiberglass tire claims that its average life will be at least 40,000 miles. To verify this claim, sample of 15 tires are tested. Sample mean was 41.1 (in 1000 miles), and sample standard deviation was 2.50. Assuming the measurements were random sample from a Normal distribution, calculate 95% one-sided confidence interval for true mean tire life. Choose lower-bound or upper-bound, whichever is appropriate. (Round to 2 decimals.) Your Answer: Answer
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