Question

we have a password that consists of n digits(0….9)
Create a swift program that let the user enters n and then find how many different password combination we could have and print no of them (upon the user choice )randomly.

Answer 1

import Foundation

func randomPassword(length: Int) -> String {

    let chars : NSString = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789~`!@#$%^&*()_+{}[]-=:?><,./"
    let len = UInt32(chars.length)

    var Passwords = ""

    for _ in 0 ..< length {
        let rand = arc4random_uniform(len)
        var nextChar = chars.character(at: Int(rand))
        Passwords += NSString(characters: &nextChar, length: 1) as String
    }

    return Passwords
}

print("Enter the number of digits[0-9]: ")
let n = Int(readLine(strippingNewline: true)!)! // taking integer input from user
print(n)

// We assume the password contains all the printable characters of ascii set i.e 95

let nn = Double(n) // First converting the integer value to use the pow function
let number = pow(95.0, nn) // calculating the number of combinations possible

print("The number of combinations possible for", n , "digits are:", number)

print("Enter the number of passwords to show: ")
let N = Int(readLine(strippingNewline: true)!)! // taking integer input from user

// Using for loop to print all the passwords

for _ in 1...N{
    let pass = randomPassword(length : n)
    print(pass)
}