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A 840 kg automobile is sliding on an icy street. It collides with a parked car...

A 840 kg automobile is sliding on an icy street. It collides with a parked car which has a mass of 592 kg. The two cars lock up and slide together with a speed of 19.4 km/h. What was the speed of the first car just before the collision?

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Answer #1

Solution :

The problem can be solved by momentum conservation.

Initial momentum = final momentum

840 x u + 592 ×0 = (840+592)× 19.4

So u = 33.07 Km/h

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