The equilibrium constant is given for one of the reactions below. Determine the value of the missing equilibrium constant.
2HD(g) ⇌ H2(g) + D2(g) Kc =
0.28
6H2(g) + 6D2(g) ⇌ 12HD(g) Kc =
?
A) 0.00048
B) 1.2
C) 1.62
D) 2075
E) 0.81
*Please explain how to do this problem! Thank you!
The 1st reaction is:
2 HD(g) <—> H2(g) + D2(g)
Kc1 = [H2][D2]/[HD]^2
= 0.28
The 2nd reaction is:
6 H2(g) + 6 D2(g) <—> 12 HD(g)
Kc = [HD]^12 / [H2]^6[D2]^6
= (1/Kc1)^6
= (1/0.28)^6
= (3.57)^6
= 2075
Answer: D
The equilibrium constant is given for one of the reactions below. Determine the value of the...
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