A buffer is to be made up with a mixture of H2PO4- and HPO42-, how many grams of HPO42- is needed for a buffer of pH=7.5 if the solution contains .0015 mol of H2PO4-
Ka of H2PO4- is 6.2x10-8
A buffer is to be made up with a mixture of H2PO4- and HPO42-, how many...
1. A buffer is prepared using 0.20 mol of H2PO4 and 0.10 mol of HPO42 in 500 mL of solution. Will the buffer capacity be exceeded if 5.6 g of KOH is added to it? What is the pH of the original solution and the pH of the new solution? (Kb 1.6 x 10-7) 2. How many milliliters of 0.113M HBr should be added to 52.2 ml of 0.0134 M morpholine to give a pH of 8? (The pKa of...
a buffer solution in which [h2po4-]=[HPO4-2]=0.132 Ka=6.2x10-8 a) what is the pH of the buffer when you add 100mL H2O to the mixture? b) what is the PH of the Buffer of the mixture? c) what is the pH of the buffer after adding 0.425 g NaOH in 2 liters of the buffer?
A buffer, consisting of H2PO4- and HPO42-, helps control the pH of physiological fluids. Many carbonated soft drinks also use this buffer system. What is the pH of a soft drink in which the major buffer ingredients are 7.30 g of NaH2PO4 and 7.80 g of Na2HPO4 per 355 mL of solution?
1. If you are to make 1 L of a 0.1 M H2PO4- / HPO42- (pKa2 = 6.9) buffer at pH 6.9 and you start with the NaH2PO4, how many grams of NaH2PO4 is needed? Do you then add HCl or NaOH to make the final buffer and how moles of HCl or NaOH is needed? MW for NaH2PO4 is 120.
Acid Acid Dissociation Constant, Ka H3PO4 7 x 10-3 H2PO4- 8 x 10-8 HPO42- 5 x 10-13 On the basis of the information above, a buffer with a pH = 9 can best be made by using A. H3PO4 + H2PO4- B. H2PO4- + PO43- C. H2PO4- + HPO42- D. HPO42- + PO43-
Calculate the ratio of the molar concentrations of HPO42- and H2PO4- ions required to obtain a buffer solution at pH = 7.0. For phosphoric acid, Ka1 = 7.5 × 10-3 Ka2 = 6.2 × 10-8 Ka3 = 4.2 × 10-13
Calculate the pH and the equilibrium concentrations of H2PO4-, HPO42- and PO43- in a 0.0287 M aqueous phosphoric acid solution. For H3PO4, Ka1 = 7.5×10-3, Ka2 = 6.2×10-8, and Ka3 = 3.6×10-13 pH = [H2PO4-] = [HPO42-] = [PO43-] =
A buffer is made by mixing equal amounts of weak acid H2PO4 and its conjugate base PO42-. The chemical equation for the buffer is H2PO4 + H20 = P042- + H30+ Calculate the pH of the buffer solution knowing that Ka-6.3x10-8
Design a buffer that has a pH of 4.77 using one
of the weak acid/conjugate base systems shown below.
Weak Acid
Conjugate Base
Ka
pKa
HC2O4-
C2O42-
6.4×10-5
4.19
H2PO4-
HPO42-
6.2×10-8
7.21
HCO3-
CO32-
4.8×10-11
10.32
How many grams of the potassium salt of the
weak acid must be combined with how many grams of the
potassium salt of its conjugate base, to produce
1.00 L of a buffer that is 1.00 M
in the weak base?
grams potassium...
Calculate the pH of a buffered solution that is 0.35 M H2PO4- and 0.75 M HPO42-. The Ka = 6.2 x 10-8.