Suppose that P(E)=0.36 P(F)=0.12 and E and F are mutually exclusive. What is P(E and F)...
Suppose that
P(E)=0.36
P(F)=0.12
and E and F are mutually exclusive. What is P(E and F)
Upper P left parenthesis Upper E or Upper F right parenthesisP(E or F)?
Homework Answers
Given,
P(E) = 0.36, P(F) = 0.12,
E and F are mutually exclusive.
P(E and F) = 0
P(E or F) = P(E) + P(F) - P(E and F)
P(E or F) = 0.36 + 0.12 - 0
P(E or F) = 0.48
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