Question 3: Let’s say if you estimate a linear regression equation to be Y= 20 + 4.2x + error, where x= pounds gained in weight and Y equals to miles run before running out of breath. If we know that r squared = 0.64, what can be said below for parts a and b.
2.) That the correlation coefficient is r= - 0.80
3.) That 64% of the variation in y (miles run) is explained by 64% in x (gained pounds)
4.) #2 and #3
5.) All of the above
2.) pounds gained in weight (x) explains y (miles run) 80% of the time
3.) The correlation between miles run (y) and pounds gained (x) is -0.8
4.) All of the above
5.) None of the above
A. Ans : 5.) All of the above
B. Ans : 1.) The correlation between miles run (y) and pounds gained (x) is 0.8
(since r squared = 0.64 and all terms in Y= 20 + 4.2x + error are positive)
Question 3: Let’s say if you estimate a linear regression equation to be Y= 20 +...
You are given the following regression equation for a scatter plot which The displays data for X= weight of car (in pounds) and y= Miles per gallon in City: Equation: y=-0.006x + 42.825 and r2= 0.7496. a. find the value of r2 based on the information given. b. Based on your value of r, what conclusion can you make about the correlation of this data? c. What does the value of r2 tell you about the regression? d. Use the...
You are given the following regression equation for a scatter plot which The displays data Weight of Car (in pounds) and y = Miles per Gallon in City: for x = y = -0.006.0 + 42.825 p2 = 0.7496 (Note: The scatter plot graph is attached to the Canvas assignment as a separate document.) (a) Find the value of r based on the information given. (b) Based on your value of r, what conclusion can you make about the correlation...
13. You are given the following regression equation for a scatter plot which The displays data for x = Weight of Car (in pounds) and y = Miles per Gallon in City: y = −0.006x + 42.825 r2 = 0.7496 (Note: The scatter plot graph is attached to the Canvas assignment as a separate document.) (a) Find the value of r based on the information given. (b) Based on your value of r, what conclusion can you make about the...
A random sample of 15 weeks of sales (measured in $) and 15 weeks of advertising expenses (measured in $) was taken and the sample correlation coefficient was found to be r = 0.80. Based on this sample correlation coefficient we could state A. That the percentage of the variation in sales that is shared with the variation in advertising is about 80%. B. That the percentage of the variation in sales that is shared with the variation in advertising...
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Use the given data to find the equation of the regression line. Examine the scatterplot and identify a characteristic of the data that is ignored by the regression line. X 5 14 13.31 13 13.66 12 13.74 10 13.05 9 12.30 4 4.31 6 8.34 8 11.25 11 13.54 7 9.94 y 6.46 = 3.00 + 0.80 (Round to two decimal places as needed.) The data show the chest size and weight of several bears. Find the...
3. The height y in inches, aud weight x in pounds of four people are recorded in a table. Weight x 150 180 200 220 lHeight y 60 64 72 74 (a) Compute the quantities i,y, sr. Sy, cry and r (b) What type of correlation is indicated? (c) Find the regression line for the bivariate data (d) Suppose a person weighs 195 pounds, what estimate would you give for the persons height?
(13 points) Suppose you have a simple linear regression model such that Y; = Bo + B18: +€4 with and N(0,0%) Call: 1m (formula - y - x) Formula: F=MSR/MSE, R2 = SSR/SSTO ANOVA decomposition: SSTOSSE + SSR Residuals: Min 1Q Modian -2.16313 -0.64507 -0.06586 Max 30 0.62479 3.00517 Coefficients: Estimate Std. Error t value Pr(> It) (Intercept) 8.00967 0.36529 21.93 -0.62009 0.04245 -14.61 <2e-16 ... <2e-16 .. Signif. codes: ****' 0.001 '** 0.01 '* 0.05 0.1'' 1 Residual standard...
2. What is the coefficient of correlation between miles per gallon and weight? What is the sign of the correlation coefficient? Does the coefficient of correlation indicate a strong correlation, weak correlation, or no correlation between the two variables? How do you know? See Step 3 in the Python script. 3. Write the simple linear regression equation for miles per gallon as the response variable and weight as the predictor variable. How might the car rental company use this model?...
Car Weight (pounds),
x Miles per Gallon, y
1 3,765 19
2 3,984 18
3 3,530 20
4 3,175 22
5 2,580 26
6 3,730 18
7 2,605 25
8 3,772 18
9 3,310 20
10 2,991 24
11 2,752 25
The accompanying data represent the weights of various domestic cars and their gas mileages in the city. The linear correlation coefficient between the weight of a car and its miles per gallon in the city is r= -0.97 The...
Show work please, Thanks!
Question 3: The regression line equation for a set of data is given by y-hat = 2.3x+5 with n = 10. The mean value of y is 10.1 for the data set. Use a = 0.05. A. If the linear correlation coefficient is r=0.521, what is the best predicted y-value for x = 5? Justify for your answer. B. If the linear correlation coefficient is r = 0.972, what is the best predicted y-value for x...