The decay of a radioisotope has a rate constant of 0.09 s-1 . How much time...
The decay of a radioisotope has a rate constant of 0.09 s-1 . How much time is required for 3/4 of a 1-gram sample of the isotope to decay?
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Homework Answers
we have:
[A]o = 1 g
3/4 of 1 g has decayed.
[A] = 1/4 of 1 g = 0.25 g
k = 0.09 s-1
use integrated rate law for 1st order reaction
ln[A] = ln[A]o - k*t
ln(0.25) = ln(1) - 0.09*t
-1.386 = 0 - 0.09*t
0.09*t = 1.386
t = 15.4 s
Answer: 15.4 s
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