Question

Q. 8)

What is the temperature (°C) of 0.198 moles of air in lungs with a capacity of 5.41 L at an atmospheric pressure of 0.934 atm?

Group of answer choices

A.) 310°C

B.) 273°C

C.) 37.3°C

D.) 583°C

Q 10.)

A sample of nitrogen gas has a volume of 0.180 L, at a pressure of 0.800 atm and a temperature of 29°C. What is the new temperature (°C) of the gas at a volume of 90.0 mL and a pressure of 3.20 atm?

Group of answer choices

A. )288°C

B.) 273°C

C.) 604°C

D.)331°C

Answer 1

8)

Answer : C.) 37.3°C

moles = 0.198

volume = 5.41 L

pressure = 0.934 atm

P V = n R T

0.934 x 5.41 = 0.198 x 0.0821 x T

T = 310.8 K

temperature = 37.3 oC

Q 10.)

volume V1 = 0.180 L

pressure P1 = 0.800 atm

temperature T1 = 29 oC = 302 K

V2 = 0.090 L

P2 = 3.20 atm

P1 V1 / T1 = P2 V2 / T2

0.800 x 0.180 / 302 = 3.20 x 0.090 / T2

T2 = 604 K

temperature = 331°C