A city is spending $ 19.2 million on a new sewage system. The expected life of the system is 45 years, and it will have no market value at the end of its life. Operating and maintenance expenses for the system are projected to average $ 0.6 million per year. If the city's MARR is 7% per year, What is the capitalized worth of the system? The study period is 100. (Using CW method)
AW = -19200000*(A/P,7%,45)-600000
= -19200000*(0.0735)-600000
= -1411200-600000
= -2011200
CW = -2011200/0.07
= -28731428.57
A city is spending $ 19.2 million on a new sewage system. The expected life of...
A city is spending $20 million on a new sewage system. The expected life of the system is 40 years, and it will have no market value at the end of its life. Operating and maintenance expenses for the system are projected to average $0.6 million per year. If the city's MARR is 8% per year, what is the capitalized worth of the system?
A city is spending $19.5 million on a new sewage system. The expected life of the system is 50 years, and it will have no market value at the end of its life Operating and maintenance expenses for the system are projected to average $0.4 million per year. If the city's MARR IS 11% per year, what is the capitalized worth of the system? The study period is 100 years. Click the icon to view the interest and annuity table...
A city is spending $20 million on a new wastewater treatment plant. The expected life of the system is 40 years, and it will have a market value of $5 million at the end of its useful lifetime. Operating and maintenance expenses for the system are projected to be $1 million per year. If the city’s MARR is 8% per year, what is the annual worth of the system? Express your answer in terms of dollars, rounded to the nearest...
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a new utility service truck can be purchase for $64,532. its expected useful like is six years, at which time its market value will the zero. Annual receipts less expenses will be approximately $24,162 per year over the six year study period. compute present worth(pw) with a MARR of 20% to determine wheter this is good investment. life*
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