Consider the following reaction:
I2(g)+Cl2(g) ⇌ 2ICl(g)
Kp= 81.9 at 25 ∘ C.
Calculate ΔGrxn for the reaction at 25 ∘ Cunder
each of the following conditions.
PICl= 2.65 atm ;
PI2= 0.320 atm ;
PCl2= 0.221 atm .
Answer
∆Grxn = 0.48 kJ/mol
Explanation
∆G°rxn = - RTlnKp
∆G°rxn = - (0.008314kJ/mol K × 298.15K × 2.303 × log(81.9)
∆G°rxn = - 10.92 kJ/mol
I2(g) + Cl2(g) <------> 2ICl(g)
Kp = (PICl)2/(PI2× PCl2)
reaction quotient, Q= (PICl, initial)2/(PI2,initial × PCl2, initial)
Q = (2.65atm)2/(0.320am){0.221atm) = 99.3
∆Grxn = ∆G°rxn + RTlnQ
= -10.92 kJ/mol + (0.008314 kJ/mol K × 298.15K ×2.303×log( 99.3)
= -10.92 kJ + 11.40 kJ
= 0.48 kJ/mol
Consider the following reaction: I2(g)+Cl2(g) ⇌ 2ICl(g) Kp= 81.9 at 25 ∘ C. Calculate ΔGrxn for the reaction at 25 ∘ Cunder each of the...
Consider the following reaction: I2(g)+Cl2(g) ⇌ 2ICl(g) Kp= 81.9 at 25 ∘ C. Calculate ΔGrxn for the reaction at 25 ∘ C under each of the following conditions. PICl= 2.58 atm ; PI2= 0.324 atm ; PCl2= 0.221 atm . Express your answer using one significant figure.
Consider the following reaction: I2(g)+Cl2(g) ⇌ 2ICl(g) Kp= 81.9 at 25 ∘ C. Calculate ΔGrxn for the reaction at 25 ∘ C under each of the following conditions. Part A. Standard conditions Part B. At equilibrium Part C. PICl= 2.59 atm PI2= 0.322 atm PCl2= 0.221 atm
Consider the following reaction: I2(g)+Cl2(g) ⇌ 2ICl(g) Kp= 81.9 at 25 ∘ C. Calculate ΔGrxn for the reaction at 25 ∘ C under each of the following conditions. PICl= 2.58 atm PI2= 0.322 atm PCl2= 0.214 atm Express your answer using one significant figure.
Consider the following reaction: I2(g)+Cl2(g) ⇌ 2ICl(g) Kp= 81.9 at 25 ∘ C. Calculate ΔGrxn for the reaction at 25 ∘ C under each of the following conditions. A) standard conditions B) at equilibrium C) P ICl= 2.56 atm ; P I2= 0.316 atm ; P Cl2= 0.215 atm .
Consider the following reaction: I2(g)+Cl2(g)⇌2ICl(g), Kp=81.9 (at 25∘C) A reaction mixture at 25∘C initially contains PI2 = 0.110 atm , PCl2 = 0.110 atm , and PICl = 0.00 atm. Find the equilibrium partial pressure of I2 at this temperature. Find the equilibrium partial pressure of Cl2 at this temperature. Find the equilibrium partial pressure of ICl at this temperature.
I2(g)+Cl2(g)⇌2ICl(g),Kp=81.9 (at 25∘C) The reaction between I2 and Cl2 is carried out at the same temperature, but with the following initial partial pressures: PI2=0.170atm, PCl2=0.170atm, and PICl=0.00 atm. find equibilibrum partial pressure of ICl.
Consider this reaction: I2(g)+Cl2(g)⇌2ICl(g) K=6.91×103 at 460 K Calculate ΔrG for the reaction at 460 K under each of the following conditions: A) Standard Conditions B) at Equilibrium C) PI2 = 0.325 bar PCl2 = 0.387 bar PICl = 2.55 bar
Consider the reaction between iodine gas and chlorine gas to form iodine monochloride: I2(g)+Cl2(g)⇌2ICl(g)Kp=81.9 (at 298 K) A reaction mixture at 298 K initially contains PI2=0.25 atm and PCl2=0.25 atm . You may want to reference (Page) Section 15.8 while completing this problem. Part A What is the partial pressure of iodine monochloride when the reaction reaches equilibrium? Express your answer to two significant figures and include the appropriate units. atm SubmitPrevious AnswersR
Consider this reaction at 298 K: H2 (g) + I2 (g) ⇌ 2 HI(g) Calculate ΔGrxn under the following conditions: PH2 (g) = 0.161 atm PI2 (g) = 0.186 atm PHI(g) = 0.307 atm
Consider the following reaction: CO(g)+2H2(g)⇌CH3OH(g) Kp=2.26×104 at 25 ∘C. Calculate ΔGrxn for the reaction at 25 ∘C under each of the following conditions. Part A: standard conditions Part B: at equalibrium Part C: PCH3OH= 1.5 atm ; PCO=PH2= 1.4×10−2 atm