Question

Last year at LAX (Los Angeles Airport) customs selected 300 people for enhanced searches. If 112 of the people selected practice Islam test against a worldwide population of 12.5% for random selection. Zα/2 = 99% or 2.58

Answer 1

using minitab>stat>basic stat>one proportion 'we have

Test and CI for One Proportion

Test of p = 0.125 vs p ≠ 0.125

Sample X N Sample p 99% CI Z-Value P-Value
1 112 300 0.373333 (0.301401, 0.445265) 13.01 0.000

since Z value is greater than 2.58 so we reject Ho and conclude that the proportion of selected practice Islam test against a worldwide population is not 12.5%