For our sample of student's measurements we expect that 68% of the values to fall within one σ (0.23mm) from our mean davg (21.00mm).
|
Diameter, mm |
# of students |
|
20.4 |
2 |
|
20.5 |
12 |
|
20.6 |
10 |
|
20.7 |
33 |
|
20.8 |
40 |
|
20.9 |
76 |
|
21.0 |
80 |
|
21.1 |
65 |
|
21.2 |
52 |
|
21.3 |
22 |
|
21.4 |
12 |
|
21.5 |
5 |
|
21.6 |
11 |
Using the data given above determine what percentage of the measurements fall within one standard deviation of the average.
For our sample of student's measurements we expect that 68% of the values to fall within...
To be done on Anova (or not)
State the hypothesis that we are testing in this problem.
Set up the null and alternative.
Comment on the degree of freedom values for each source of
variation. How do you calculate them?
Do we reject the hypothesis that we are testing? Why or why
not?
If you reject, can you tell which level(s) is probably the
one(s) that has the different mean? (Hint: use the box plots from
part 1a
Use the...
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the way this is worded confuses me. Will there be one problem
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x&y is female weight and bmi for problem 2?
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