Suppose that the weight of navel oranges is normally distributed with mean=8 ounces and standard deviation = 1.5 ounces.
What is the weight of the navel orange larger than only 10% of navel oranges.
for top 10 % will fall at 90th percentile:
| for 90th percentile critical value of z= | 1.28 | ||
| therefore corresponding value=mean+z*std deviation= | 9.92 ounces | ||
Suppose that the weight of navel oranges is normally distributed with mean=8 ounces and standard deviation...
Suppose that the weight of Florida navel oranges is normally distributed with mean µ = 8 ounces, and standard deviation σ = 1.5 ounces. (a) (1 point) State the model in notation form. (b) (2 points) What proportion of oranges weigh more than 11.5 ounces? (c) (2 points) What proportion of oranges weigh less than 8.7 ounces? (d) (2 points) What proportion of oranges weigh between 6.2 and 7 ounces? Page 3 (e) (5 points) What are the median, mode,...
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the weights of oranges are normally distributed with a mean weight of 150 grams and a standard deviation of 10 grams. In a sample of 100 oranges, how many will weigh between 130 and 170 grams?
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