Suppose that a random sample of 100 observations from a population gives a value \hat{p} p ^ =.68 and you wish to test the null hypothesis that p = .75 against the alternate hypothesis that p<.75 Find the p-value for the test correct to 3 decimal places.
Solution :
This is the left tailed test .
The null and alternative hypothesis is
H0 : p =0.75
Ha : p <0.75
= 0.68
P0 = 0.75
1 - P0 = 1-0.75=0.25
Test statistic = z
=
- P0 / [
P0
* (1 - P0 ) / n]
=0.68-0.75 / [
(0.75*0.25)
/ 100]
Z= -1.62
P(z <-1.62 ) = 0.0526 ( using z table )
P-value = 0.053
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