A 10Mbps (1M = 10^6) CSMA/CD network has a distance of 5000 m between stations sharing...
A 10Mbps (1M = 10^6) CSMA/CD network has a distance of 5000 m between stations sharing the link. The data frame is 512 bits long. The speed of the signal is 2x10^8m/s
1. Find the total time spent to transmit one frame (including transmission and propagation time)
2. Does the frame length of 512 bits work for a new 100 Mbps CSMA/CD network of this length? Why?
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A 10Mbps (1M = 10^6) CSMA/CD network has a distance of 5000 m
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