In the dataset StudentSurvey, 365 students recorded the number of hours of television they watched per...
In the dataset StudentSurvey, 365 students recorded the number of hours of television they watched per week. The average is ¯x=7.504 hours with a standard deviation of 4.984. Find a 95% confidence interval for μ and interpret the interval in context. In particular, be sure to indicate the population involved.
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In the dataset StudentSurvey, 365 students recorded the number
of hours of television they watched per...
2. In estimating the mean number of television viewing hours per family per week, a random...
2. In estimating the mean number of television viewing hours per family per week, a random sample of 400 families yields a mean of 32.6 hours and a standard deviation of 9.9 hours (a) Find a 95% confidence interval for the average number of viewing hours per family per week in the population. Interpret. (b) Find a 99% confidence interval for the average number of viewing hours per family per week in the population. Interpret. (c) Suppose instead only 25...
QUESTION 5 In order to determine how many hours per week freshmen college students watch television,...
QUESTION 5 In order to determine how many hours per week freshmen college students watch television, a random sample of 256 students was selected. It was determined that the students in the sample spent an average of 14 hours with a standard deviation of 3.6 hours watching TV per week. a. Provide a 95% confidence interval estimate for the average number of hours that all college freshmen spend watching TV per week. Assume that a sample of 66 students was...
Based on a random sample of 20 students from a PE class, they exercise 1.6 hours...
Based on a random sample of 20 students from a PE class, they exercise 1.6 hours (96 minutes) per day on average with sample standard deviation 1.23 hours (78 minutes). Use this information to construct a 95% confidence interval to estimate μ, the population mean number of hours of daily exercise for students. a. State the assumption(s) b. identify whether each assumption is met or not. c. Show your work to calculate the confidence interval and d. interpret the result in...
a-c please 3. In order to determine how many hours per week freshmen college students watch...
a-c please
3. In order to determine how many hours per week freshmen college students watch television, a random sample of 25 students was selected. It was determined that the students in the sample spent an average of 19.5 hours with a sample standard deviation of 3.9 hours watching TV per week. Please answer the following questions: (a) Provide a 95% confidence interval estimate for the average number of hours that all college freshmen spend watching TV per week. (b)...
3. In a recent study of 100 eighth graders, the mean number of hours per week...
3. In a recent study of 100 eighth graders, the mean number of hours per week that they watched television was 22.6. Assume the population standard deviation, o, is 5.2 hours. (Section 6.1) Construct a 90% confidence interval for the population mean number of hours that eighth graders watch television • Margin of error, E..8554 Confidence interval:al: 74<us 23.46 If the population standard deviation was reduced by 50% to 2.6 and the level of confidence remained at 90%, what would...
4. A survey asked a random sample of 363 first-year students how many hours they studied...
4. A survey asked a random sample of 363 first-year students how many hours they studied during a particular week. The mean was 15.3 hours. Suppose we know that the population standard deviation is 8.5 hours. Construct a 90%, 95% and 99% confidence interval for the mean study time of all first year students at this university. Interpret the 90% confidence interval.
Now assume that instead of a sample of 365 kindergarten students, your sample consisted of 16...
Now assume that instead of a sample of 365 kindergarten
students, your sample consisted of 16 randomly selected kids. Find
the 95% confidence interval of the mean for all kindergarteners in
the US.
A study of 365 randomly-selected kindergarten students across the US revealed that they had seen an average of 3000 hours of television. If the standard deviation is 300, us distribution find the 95% confidence interval of the mean for all kindergarteners in the U 5) e the...
A market researcher for a consumer electronics company wants to study the television viewing habits of...
A market researcher for a consumer electronics company wants to study the television viewing habits of residents of a particular area. A random sample of 40 respondents is selected, and each respondent is instructed to keep a detailed record of all television viewing in a particular week. The results are as follows: • Viewing time per week: Xbar = 15.3 hours, S = 3.8 hours. • 27 respondents watch the evening news on at least three weeknights. Construct a 95%...
3. Twenty students are questioned about their leisure activities. These students spend an average of 18.5...
3. Twenty students are questioned about their leisure activities. These students spend an average of 18.5 hours per week watching streaming video services. The standard deviation for watching streaming videos is 3.2 hours per week. Construct a 95% confidence interval for the mean number of hours of streaming videos watched by all students.
1. To determine the average number of hours spent studying by college students per week, a...
1. To determine the average number of hours spent studying by college students per week, a sample of 39 students was randomly selected, and found to spend an average of 17.1 hours per week, with a standard deviation of 4.3 hours. Find the 90% confidence interval for the mean number of hours spent studying per week by all college students. What is the upper and lower bound? 2. If I asked a random student how many hours they study per...
2. In estimating the mean number of television viewing hours per family per week, a random sample of 400 families yields a mean of 32.6 hours and a standard deviation of 9.9 hours (a) Find a 95% confidence interval for the average number of viewing hours per family per week in the population. Interpret. (b) Find a 99% confidence interval for the average number of viewing hours per family per week in the population. Interpret. (c) Suppose instead only 25...
QUESTION 5 In order to determine how many hours per week freshmen college students watch television, a random sample of 256 students was selected. It was determined that the students in the sample spent an average of 14 hours with a standard deviation of 3.6 hours watching TV per week. a. Provide a 95% confidence interval estimate for the average number of hours that all college freshmen spend watching TV per week. Assume that a sample of 66 students was...
a-c please
3. In order to determine how many hours per week freshmen college students watch television, a random sample of 25 students was selected. It was determined that the students in the sample spent an average of 19.5 hours with a sample standard deviation of 3.9 hours watching TV per week. Please answer the following questions: (a) Provide a 95% confidence interval estimate for the average number of hours that all college freshmen spend watching TV per week. (b)...
3. In a recent study of 100 eighth graders, the mean number of hours per week that they watched television was 22.6. Assume the population standard deviation, o, is 5.2 hours. (Section 6.1) Construct a 90% confidence interval for the population mean number of hours that eighth graders watch television • Margin of error, E..8554 Confidence interval:al: 74<us 23.46 If the population standard deviation was reduced by 50% to 2.6 and the level of confidence remained at 90%, what would...
4. A survey asked a random sample of 363 first-year students how many hours they studied during a particular week. The mean was 15.3 hours. Suppose we know that the population standard deviation is 8.5 hours. Construct a 90%, 95% and 99% confidence interval for the mean study time of all first year students at this university. Interpret the 90% confidence interval.
Now assume that instead of a sample of 365 kindergarten
students, your sample consisted of 16 randomly selected kids. Find
the 95% confidence interval of the mean for all kindergarteners in
the US.
A study of 365 randomly-selected kindergarten students across the US revealed that they had seen an average of 3000 hours of television. If the standard deviation is 300, us distribution find the 95% confidence interval of the mean for all kindergarteners in the U 5) e the...
3. Twenty students are questioned about their leisure activities. These students spend an average of 18.5 hours per week watching streaming video services. The standard deviation for watching streaming videos is 3.2 hours per week. Construct a 95% confidence interval for the mean number of hours of streaming videos watched by all students.
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