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An aqueous NaCl solution is made using 119 g of NaCl diluted to a total solution volume of 1.25 L . |
Part A Calculate the molarity of the solution. Part B Calculate the molality of the solution. (Assume a density of 1.08 g/mL for the solution.) Express your answer using two significant figures. Part C Calculate the mass percent of the solution. (Assume a density of 1.08 g/mL for the solution.) |
Part A : mass of NaCl = 119 g
moles of NaCl = (mass of NaCl) / (molar mass NaCl)
moles of NaCl = (119 g) / (58.44 g/mol)
moles of NaCl = 2.04 mol
molarity of solution = (moles of NaCl) / (volume of solution (L))
molarity of solution = 2.04 mol / 1.25 L
molarity of solution = 1.6 M
Part B :
mass of solution = (volume of solution) * (density of solution)
mass of solution = (1250 mL) * (1.08 g/mL)
mass of solution = 1350 g
mass of water = mass of solution - mass of NaCl
mass of water = 1350 g - 119 g
mass of water = 1231 g
mass of water = 1.231 kg
molality of NaCl = moles of NaCl / mass of water (kg)
molality of NaCl = 2.04 mol / 1.231 kg
molality of NaCl = 1.7 m
Part C :
mass percent of solution = (mass of NaCl / mass of solution) * 100
mass percent of solution = (119 g / 1350 g) * 100
mass percent of solution = 8.8 %
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