A parallel-plate vacuum capacitor has 9.22 J of energy stored in it. The separation between the plates is 2.00 mm . If the separation is decreased to 1.25 mm ,
Part A
what is the energy now stored if the capacitor was disconnected from the potential source before the separation of the plates was changed?
Part B
What is the energy now stored if the capacitor remained connected to the potential source while the separation of the plates was changed?
Concept - use the equation for energy in a
capacitor and the relation between capacitance, voltage and charge
to find the required solution as shown below
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A parallel-plate vacuum capacitor has 9.22 J of energy stored in it. The separation between the...
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