Question

The U.S Department of Agriculture provides data on the monthly average price of a gallon of...

The U.S Department of Agriculture provides data on the monthly average price of a gallon of whole milk. The table below gives values for 2010.

Date Price ($) Date Price ($)
1/10 3.24 7/10 3.31
2/10 3.20 8/10 3.30
3/10 3.19 9/10 3.29
4/10 3.14 10/10 3.32
5/10 3.18 11/10 3.33
6/10 3.30 12/10 3.32

a. What is the most appropriate graph type for this data?

b. Graph this data

0 0
Add a comment Improve this question Transcribed image text
Answer #1

A). Histogram is most appropriate graph type for this data

B).

Add a comment
Know the answer?
Add Answer to:
The U.S Department of Agriculture provides data on the monthly average price of a gallon of...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Market Distortion - Price Floors Exercise 1 (Algo) The U.S. Department of Agriculture guarantees dairy producers...

    Market Distortion - Price Floors Exercise 1 (Algo) The U.S. Department of Agriculture guarantees dairy producers that they will receive at least $1.00 per pound for butter supply to the market. Below is the current monthly demand and supply schedules for wholesale butter (in millions of pou per month). Market for Wholesale Butter Quantity of Butter Demanded Quantity of k Butter Supplied (millions of pounds) (millions of Price (dollars pounds) per pound) $0.80 63 107 71 104 0.90 79 101...

  • bug fix of python here's the program: import binascii file = open("nibbles.txt", "r") count = 1...

    bug fix of python here's the program: import binascii file = open("nibbles.txt", "r") count = 1 bytes = "" message = "" for i, line in enumerate(file): startIndex = line.index('(') endIndex = line.index(')') co = line[startIndex:endIndex+1] # (-1.35, 2.30) coordinates = line[startIndex+1:endIndex] # -1.35, 2.30 comma = coordinates.index(',') iVoltage = coordinates[0:comma] iv = float(iVoltage) qVoltage = coordinates[comma+2:] qv = float(qVoltage)    if iv >= 0 and iv <= 2 and qv >= 0 and qv <= 2: point = "1101"...

  • The subjects in the data are college students. In the data, id is student ID, anxiety...

    The subjects in the data are college students. In the data, id is student ID, anxiety is student’s anxiety score via Anxiety Scale, selfest is student’s self-esteem score via Rosenberg Self-esteem Scale, GPA is student’s GPA; for gender, 0=female, 1=male; for grade, 1=freshman, 2=junior, 3=senior. We have known that population mean for Anxiety Scale is μ=60 with σ=10. Raise relevant questions ( 2 questions is fine) about the data extensively, the questions can be either about descriptive analysis or inferential...

  • Gain (V/V) R Setting Totals Averages Sample 1 Sample 2 Sample 3 4 ап 7.8 8.1...

    Gain (V/V) R Setting Totals Averages Sample 1 Sample 2 Sample 3 4 ап 7.8 8.1 7.9 3 5.2 6.0 4.3 = 359.3 i=1 j=1 2 4.4 6.9 3.8 1 2.0 1.7 0.8 This is actual data from one of Joe Tritschler's audio engineering experiments. Use Analysis of Variance (ANOVA) to test the null hypothesis that the treatment means are equal at the a = 0.05 level of significance. Fill in the ANOVA table. Source of Variation Sum of Squares...

  • Gain (V/V) R Setting Totals Averages Sample 1 Sample 2 Sample 3 4 ап 7.8 8.1...

    Gain (V/V) R Setting Totals Averages Sample 1 Sample 2 Sample 3 4 ап 7.8 8.1 7.9 3 5.2 6.0 4.3 = 359.3 i=1 j=1 2 4.4 6.9 3.8 1 2.0 1.7 0.8 This is actual data from one of Joe Tritschler's audio engineering experiments. Use Analysis of Variance (ANOVA) to test the null hypothesis that the treatment means are equal at the a = 0.05 level of significance. Fill in the ANOVA table. Source of Variation Sum of Squares...

  • Suppose 1000 coins are tossed. Use the normal curve approximation to the binomial distribution to find...

    Suppose 1000 coins are tossed. Use the normal curve approximation to the binomial distribution to find the probability of getting the following result. Exactly 495 heads Use the table of areas under the standard normal curve given below. Click here to view page 1. Click here to view page 2. Click here to view page 3. Click here to view page 4. Click here to view page 5. Click here to view page 6. The probability of getting exactly 495...

  • Suppose 16 coins are tossed. Use the normal curve approximation to the binomial distribution to find...

    Suppose 16 coins are tossed. Use the normal curve approximation to the binomial distribution to find the probability of getting the following result. More than 11 tails. Use the table of areas under the standard normal curve given below. Click here to view page 1. Click here to view page 2. Click here to view page 3. Click here to view page 4. Click here to view page 5. Click here to view page 6. Binomial probability = (Round to...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT