an astronaut on a distant planet wants to determine its acceleration due to gravity . the...
An astronaut on a distant planet wants to determine its acceleration due to gravity. The astronaut throws a rock straight up with a velocity of +18.9 m/s and measures a time of 16.1 s before the rock returns to his hand. What is the acceleration (magnitude and direction) due to gravity on this planet? (positive = up, negative = down)
An astronaut on a distant planet wants to determine its acceleration due to gravity. The astronaut throws a rock straight up with a velocity of +17.9 m/s and measures a time of 22.0 s before the rock returns to his hand. What is the acceleration (magnitude and direction) due to gravity on this planet? (positive = up, negative = down)
An astronaut on a distant planet wants to determine its acceleration due to gravity. The astronaut throws a rock straight up with a velocity of +15 m/s and measures a time of 20.0 s before the rock returns to his hand. What is the acceleration (magnitude and direction) due to gravity on this planet? See Diagram below: Show your work below:
Concept Simulation 2.3 offers a useful review of the concepts central to this problem. An astronaut on a distant planet wants to determine its acceleration due to gravity. The astronaut throws a rock straight up with a velocity of +15.0 m/s and measures a time of 15.1 s before the rock returns to his hand. What is the acceleration (magnitude and direction) due to gravity on this planet? (positive-up, negative-down) Number Units the tolerance is +/-5%
6. An astronaut ona distant planet wants to determine its acceleration due to gravity. The astronaut throws a rock straight up with a velocity of +15 m/s and measures a time of 20.0 s before the rock returns to his hand. What is the acceleration (magnitude and direction) due to gravity on this planet? See Diagram below: 20.0s v,15 m/s Show your work below: 7. Problem using vectors: A sailboat sails for 1 hr at 4 km/hr (relative to the...
1.) a.) The velocity of a diver just before hitting the water is -7 m/s, where the minus sign indicates that her motion is directly downward. What is her displacement during the last 1.03 s of the dive? ______m b.) An astronaut on a distant planet wants to determine its acceleration due to gravity. The astronaut throws a rock straight up with a velocity of +12 m/s and measures a time of 18.0 s before the rock returns to his...
1. Concept Simulation 2.3 offers a useful review of the concepts central to this problem. An astronaut on a distant planet wants to determine its acceleration due to gravity. The astronaut throws a rock straight up with a velocity of +21.4 m/s and measures a time of 22.0 s before the rock returns to his hand. What is the acceleration (magnitude and direction) due to gravity on this planet? (positive = up, negative = down) 2. A golf ball is...
Suppose you are an astronaut and you have been stationed on a distant planet. You would like to find the acceleration due to the gravitational force on this planet so you devise an experiment. You throw a rock up in the air with an initial velocity of 9 m/s and use a stopwatch to record the time it takes to hit the ground. If it takes 5.2 s for the rock to return to the same location from which it...
An astronaut shipwrecked on a distant planet with unknown characteristics is on top of a cliff, which she wishes to descend. She does not know the acceleration due to gravity on the planet, and she has only a good watch with which to make measurements. She wants to learn the height of the cliff, and to do this she makes two measurements. First, she lets the rock fall from rest off the cliff edge; she finds that the rock takes...
7. An astronaut shipwrecked on a distant planet with unknown characteristics is on top of a cliff, which he wishes to descend He does not know the acceleration due to gravity on the planet. and he has only a good watch with which to make measurements. He wants to learn the height of the cliff, and to do this, he makes two measurements (Fig. 2-2 ). First, he lets a rock fall from rest off the cliff edge; he finds...