Determine how long 100$ must be left to accumulate at j12 = 18% for it to amount to twice the accumulated value of another $100 deposited at the same time at j2 = 10%. Ans; 8.55 years
100*(1+18%/12)^(12*t)=2*100*(1+10%/2)^(2*t)
=>12*t*log(1+18%/12)=log2+2*t*log(1+10%/2)
=>t*(12*log(1+18%/12)-2*log(1+10%/2))=log2
=>t=log(2)/(12*log(1+18%/12)-2*log(1+10%/2))
=>t=8.548 years
Determine how long 100$ must be left to accumulate at j12 = 18% for it to...
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