A lead vat is 16 m long at room temperature (20°C). How much longer is it when it contains boiling water at 1 atm pressure?
Expression for the liner expression is
∆L/L0 =2 ∆T
∆L=2*∆T*L0
=28*10^-6 * (100-20) *16
∆t=0.03584 m Answer
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