A mole of an ideal gas expands from a initial volume of 7 L to 15...
A mole of an ideal gas expands from a initial volume of 7 L to 15 L at a constant temperature of 340 K. How much work is done by the expanding gas? The gas constant, R, is 8.31 J/mol∙K.
-2153 J
935 J
2825 J
2153 J
Homework Answers
Given, Vi = 7 L
Vf = 15 L
and, T = 340 K
Since, Workdone in isothermal process is given by: W = nRT ln (Vf/Vi)
Therefore, W = (1 mol)(8.31 J/mol∙K.)(340 K) ln (15/7) = 2153 J
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