Student grades in a sufficiently large class tend to follow a normal distribution. Suppose the final exam of a class follows a normal distribution with a mean of 75 and a standard deviation of 7.5. Select a score of 95 and specify its z-score based on this distribution.
When calculating the z-score, include the steps leading to the workings. That way, any mistakes can be quickly seen and corrected. Use the chosen raw score (95) and the calculated z-score to provide a letter grade for the student. Based on these, convey a message to the audience and if possible, indicate your conclusion(s) and/or recommendation(s), if any. For example, would you recommend the student for scholarship? Is the student's performance not as good and you recommend some form of help, e.g., tutoring?
Student grades in a sufficiently large class tend to follow a normal distribution. Suppose the final...
URGENT
4. The test grades in some class follow a normal distribution (we will call it X) with o = 8. Use this information (and the chart!) to answer the following questions: (a) If there is a 60% chance that a student scores higher than a 75, find , the average test grade for this class. (b) Using the you found in part (a), determine P(72 < X <90).
c++
implement a student class
Determine the final scores, letter grades, and rankings of all
students in a course.
All records of the course will be stored in an input file, and a
record of each student will include the first name, id, five quiz
scores, two exam scores, and one final exam score.
For this project, you will develop a program named cpp to determine the final scores, letter grades, and rankings of all students in a course. All...
2. This week, we studied the test score Y versus number of hours, X, spent on test preparation, of a student in a French class of 10 students with the collected results shown below Number of hours studied Test score 31 10 14 73 37 12 60 91 21 84 17 (a) Use linear normal regression analysis method or the least-squares approximation method to predict the average test score of a student who studied 12 hours for the test (b)...