Question

A sample of sodium reacts completely with 426 gg of chlorine, forming 702 gg of sodium chloride. What mass of sodium reacted?

Answer 1

Reaction ;

2 Na + Cl2 >>>> 2 NaCl

1 mole of Na (23g/mol) gives 1 mole of NaCl(58.44g/mol)

1 gg (giga gram ) = 10^9 gram

Thus 1 g = 10^-9 gg  

As 58.44×10^-9 gg of NaCl is formed by = 23 × 10^-9 gg of Na

Then 702 gg of NaCl must be formed by = (23×10^-9gg Na/58.44×10^-9gg NaCl)×702gg NaCl = 276.28 gg of Na .

Thus 276.28 gg mass of sodium reacted .