Question

C++

Create a function called countOccurences that will count how many times a certain number occurs in the array. The function should take an array, a size and a variable, which is what you are searching for.

Heres what I got so far:

#include <iostream>
#include <string>
#include <vector>

using namespace std;

void fillArray(int a[], int size);
void printArray(int a[], int size);
int countEvens(int ar[], int size);

int main()
{
   int ar[10];

   fillArray(ar, 10);
   printArray(ar, 10);

   int count = countEvens(ar, 10);
   cout << "There are " << count << " Even numbers in the array " << endl;

   return 0;
}
void fillArray(int a[], int size)
{
   for (int i = 0; i < 10; i++)
       a[i] = rand() % 10 + 1;
}
void printArray(int a[], int size)
{
   for (int i = 0; i < 10; i++)
       cout << a[i] << "\n";
}
int countEvens(int ar[], int size)
{
   int count = 0;
   for (int i = 0; i < size; i++)
   {
       if (ar[i] % 2 == 0)
           count++;
   }

   return count;
}

Answer 1

#include <iostream>
#include <string>
#include <vector>

using namespace std;

void fillArray(int a[], int size);
void printArray(int a[], int size);
int countEvens(int ar[], int size);
int countOccurences(int ar[], int size,int key);

int main()
{
int ar[10];

fillArray(ar, 10);
printArray(ar, 10);

int count = countEvens(ar, 10);
cout << "There are " << count << " Even numbers in the array " << endl;
int count2=countOccurences(ar,10,4);
cout << "There are " << count2 << " occurences of 4 in the array " << endl;
return 0;
}
void fillArray(int a[], int size)
{
for (int i = 0; i < 10; i++)
a[i] = rand() % 10 + 1;
}
void printArray(int a[], int size)
{
for (int i = 0; i < 10; i++)
cout << a[i] << "\n";
}
int countEvens(int ar[], int size)
{
int count = 0;
for (int i = 0; i < size; i++)
{
if (ar[i] % 2 == 0)
count++;
}

return count;
}
int countOccurences(int ar[], int size,int key)
{
int count = 0;
for (int i = 0; i < size; i++)
{
if (ar[i]==key)
count++;
}
return count;
}