Question

Develop a complete C++ program to perform the following tasks:
- Implement a function that takes three parameters (x, y, z). It calculates minimum of x and y, and keeps the result in z. Return type of this function is void.
- Implement a function that takes three parameters (x, y, z). It calculates max of x and y, and keeps the result in z. Return type of this function is void.
- Implement a function that takes three parameters (x, y, z). It calculates ave of x and y, and keeps the result in z. Return type of this function is void.

Design a loop in which you ask user to enter two numbers and calculation. User enters only number between 0 and 100. Perform intended calculation until user enters 0 and 0 as operators. An example run given as

Enter two numbers: 2 5
Enter an operation 1)min 2)max 3)ave : 2
Max of 2 and 5 is 5.

Enter two numbers: 8 65
Enter an operation 1)min 2)max 3)ave : 1
Min of 8 and 65 is 8.

Enter two numbers: 16 20
Enter an operation 1)min 2)max 3)ave : 3
Ave of 16 and 20 is 18.

Enter two numbers: 40 50
Enter an operation 1)min 2)max 3)ave : 3
Ave of 40 and 50 is 45.

Enter two numbers: 0 0
Bye…

Note: Make sure that you get numbers from the user at once, such as cin >> a >> b;

Answer 1

#include <iostream>

using namespace std;
void Min(int x,int y,int z);
void Max(int x,int y,int z);
void Ave(int x,int y,int z);

int main() {
  
int op,num1,num2,Result=0;
cout<<"Enter an operation: "<<endl;
cout<<"1.Min"<<endl;
cout<<"2.Max"<<endl;
cout<<"3.ave"<<endl;
cout<<"Enter the two numbers: "<<endl;
cin>>num1>>num2;
while(num1!=0 && num2!=0)
{
cin>>op;
switch(op)
{
case 1:Min(num1,num2,Result);
break;
case 2:Max(num1,num2,Result);
break;
case 3:Ave(num1,num2,Result);
break;

}
cout<<"Enter an operation: "<<endl;
cout<<"1.Min"<<endl;
cout<<"2.Max"<<endl;
cout<<"3.ave"<<endl;
cout<<"Enter the two numbers: "<<endl;
cin>>num1>>num2;
}
cout<<"Bye Bye"<<endl;
}
void Min(int x,int y,int z)
{
if(x<y)
z=x;
else
z=y;

cout<<"Min of "<<x <<"and "<<y<<" is "<<z<<endl;
}
void Max(int x,int y,int z)
{
if(x>y)
z=x;
else
z=y;
cout<<"Max of "<<x <<"and "<<y<<" is "<<z<<endl;
}
void Ave(int x,int y,int z)
{
z=(x+y)/2;
cout<<"Ave of "<<x <<"and "<<y<<" is "<<z<<endl;
}