When a lightbulb is turned on, 6.70 C of charge pass through the filament of the bulb in 10.0 s. How many electrons pass through the filament in 5 s?
I=Q/t=6.70/10=0.670 A
Now,0.670=q/5
Q=.670 ×5=3.35 Column.
Note:- Q - charge,,i - current,,t- time
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