Arrange the following solutions in order of increasing freezing
point depression:
A. 0.10 m MgCl2 in water, i = 2.7,
Kf = 1.86°C/m
B. 0.16 m toluene in diethyl ether, i = 1.00,
Kf = 1.79°C/m
C. 0.24 m ethylene glycol in ethanol, i = 1.00,
Kf = 1.99°C/m
The freezing point depression constant is the degrees that the freezing point of the solvent is lowered when 1 mole of a solute is dissolved in 1 kg grams of the solvent.
When a solute is dissolved in a solvent, the freezing point of the solvent is lowered.
Depression in freezing point = i*Kf*m
where, Kf = cryoscopic constant for the solvent
m = molality.. moles solute / kg solvent
i = van't hoff factor = ions 1 molecule of solute dissociates into
in solution.
so order is B<C<A
Arrange the following solutions in order of increasing freezing point depression: A. 0.10 m MgCl2 in...
Arrange the following solutions in order of increasing freezing point depression. [Hint: The corresponding van’t Hoff factor (i) is given]: (a) 0.10 m MgCl2 in water, i = 2.7, Kf = 1.86°C/m for the solvent (water). (b) 0.20 m toluene in diethyl ether, i = 1.00, Kf = 1.79°C/m for the solvent (diethyl ether). (c) 0.20 m ethylene glycol in ethanol, i = 1.00, Kf = 1.99°C/m for the solvent (ethanol).
The following solutions all lower the freezing point of the given solvent.. Arrange them in order of increasing freezing point depression. a. 0.1 m MgCl, in water, i = 2.7, K_f = 1.86 degree C/m b. 0.20 m toluene in diethyl ether, i = 1.00, K_f = 1.79 degree C/m c. 0.20 m glycol methanol, i = 1.00, K_f = 1.99 degree C/m
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