An alpha particle with kinetic energy 15.0 MeVmakes a collision with lead nucleus, but it is...
An alpha particle with kinetic energy 15.0 MeVmakes a collision with lead nucleus, but it is not "aimed" at the center of the lead nucleus, and has an initial nonzero angular momentum (with respect to the stationary lead nucleus) of magnitude L=p0b, where p0 is the magnitude of the initial momentum of the alpha particle and b=1.40×10−12 m . (Assume that the lead nucleus remains stationary and that it may be treated as a point charge. The atomic number of lead is 82. The alpha particle is a helium nucleus, with atomic number 2.)
a) What is the distance of closest approach?
b) Repeat for b=1.50*10^-13 m.
c) Repeat for b=1.10*10^-14 m.
I worked this problem three times and it took me over half an hour and still got it wrong and almost snapped my laptop pls help.
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An alpha particle with kinetic energy 15.0 MeVmakes a collision
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