Use the mean value of 537 for Keq to calculate the SCN− concentration in a solution whose initial Fe3+ concentration was 3.90×10−02 M and initial SCN− concentration was 1.00×10−03 M .
Fe3+ + SCN− ⇌ FeNCS2+
I used the ice chart and determined that:
537 = x/(0.039-x)(0.001-x)
Please help me understand how to solve this question.
Use the mean value of 537 for Keq to calculate the SCN− concentration in a solution...
Use the mean value of 533 for Keq to calculate the SCN− concentration in a solution whose initial Fe3+ concentration was 4.10×10−02 M and initial SCN− concentration was 1.50×10−03 M Fe3+ +SCN- --->FeNCS2+
Use the mean value of 540 for Keq to calculate the SCN- concentration in a solution whose initial Fe3+ concentration was 3.60x10-2 M and initial SCN- concentration was 1.30x10-3 M. Give answer in M. Equation: Fe3+ + SCN- <-----------> FeNCS2+
Please try to explain this like I am a
toddler. I am VERY confused... :/
Il Review | Constants Periodic Part A and initial SCN-concentration was 1.10x10-03 M. Use the mean value of 535 for Keq to calculate the SCN- concentration in a solution whose initial Fe3+ concentration was 3.50x10-02 M Fe3+ + SCN- = FeNCS2+ IVO ACO O 2 ? 2 • 10-2 Submit Previous Answers Request Answer
Standard solutions of [Fe(SCN)2-] were prepared and their absorbance measured in order to study the Keq for the reaction Fe3+ + SCN- <=> FeNCS2+ A plot of absorbance verses concentration of [Fe(SCN)2-] is shown below. To determine the Keq for the above reaction, 10.00 mL of 0.00200 M Fe(NO3)3 solution is mixed with 5.00 mL of 0.0020 M KSCN and diluted with 5.0 mL 0f 0.10 M HNO3. The absorbance of this red solution is found to be 0.322....
At a certain temperature, Keq = 150 for the reaction being studied in today’s lab. Use Equation (3) to calculate the concentrations of Fe3+ and SCN in a solution that has an equilibrium FeSCN2+ concentration of 4.5 x 10-5 M. Assume the equilibrium concentrations of Fe3+ and SCN are equal.
thiocyanatoiron (III)ion? The path length for the light is 1.00 cm? FE(NO3)₂ + KSCN sre(SCN) KT + 3No. [NOPZ Keq & [Lee SCN ) 2+] [x+) Tre(NO3); [ilsen . 1.4 x 10² x (1-x)² = 23 x 3 X 0.77 m Keqz (3x) I Toro-x) (2.00 X 2. Assuming that the equilibrium concentration of [FeSCN2') is 6.08 x 10 Min a solution that initially was 1.00 x 10 Min Fe3+ and 2.00 x 10 Min SCN, calculate the equilibrium concentrations...
2.) Explain why the concentration of Fe(SCN)2+ is equal to the
intial concentration of the SCN- for each solution in part A?
3.) also!!
thank you!!! :)
Post-Lab Questions: A solution is made by mixing 5.00 ml. of 0.00300 M Fe(NO,)s with 4.00 mL. of 0.00300 M KSCN and 3.00 mL. of 1.0 MHNO,. After equilibrium is established, the concentration Fe(SCN)P was determined to be 2.72 x 10* M. Calculate the value of the equilibrium constant for the reaction. Fe...
Calculate the initial concentration of iron(III) in
solution #1, #2, #3.
Beaker (mL) Table 1. Reagent Solutions Provided by the Stockroom Solution Name Reagent [Reagent] (M) Volume (mL) Standard iron Fe(NO3)3 2.50 x 10 in 0.10 M HNO3 nitric acid HNO3 0.10 120 35 50 250 conc. SCN KSCN 0.50 30 50 dilute SCN KSCN 2.50 x 10-3 30 50 Worksheet 1 #1 5.00 #2 10.00 #3 15.00 Dilute iron (mL) [Fe**] (M) [Fe(SCN)?*] (M) %T 480 58.9 35.8 21.5...
What's the concentration of [FeSCN2+] using limiting
reactant theory and equation?
For each test tube solution enter the initial concentration of Fe+ and SCNthe equilibrium concentration of FeSCN2: into the ICE table given. Complete entries for the rest of the table and calculate the K value for each of the tables. The values of K should be confined to a narrow range to reflect constancy. Comment on the quality of your work in this regard and calculate the average K....