Question

Assume that the readings on the thermometers are normally distributed with a mean of 0 ∘ and a standard deviation of 1.00 ∘ C . Find P 60 , the 60 th percentile. This is the temperature reading separating the bottom 60 % from the top 40 %. (Round your answer to at least three decimal places.)

Answer 1

Solution:-

Given that,

mean = = 0

standard deviation = = 1

Using standard normal table,

P(Z < z) = 60%

= P(Z < z ) = 0.60

= P(Z < 0.253 ) = 0.60  

z = 0.253

P60 = 0.253