A 4.0 kg cart with a charge of 4.0 x 10 -5 C starts at rest on a horizontal frictionless surface 0.50 m from a fixed object with a charge of 2.0 x 10-4 C. When the cart is released. How fast is the cart moving when it has traveled 2.0 m? How fast is it moving when it is very far away from the fixed object? I know the answers are (7.35 m/s, 8.5 m/s) but not how to get there.
Use energy conservation principle where initial potential energy
is equal to sum of kinetic energy and potential energy at the
separation of 2 m. When it is very far away from the fixed object,
the potential energy will be zero. Hence in the second case,
initial potential energy is equal to final kinetic energy.
3. Evaluate the solution The problem A 2.0-kg cart with a +2.0 x 10 C charge on it starts at rest 1.0 m from a fixed dome with charge +1,0 x 10" C. The cart is qí = 1x10"C released. Determine how fast it is moving when it is 3.0 m from the fixed-charged dome. Proposed Solution PICTURE AND TRANSLATE The situation is depicted in the illustration to the right. SIMPLIFY We assume that the dome and cart are point...
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