The density of acetonitrile (CH3CN)(CH3CN) is 0.786 g/mLg/mL, and the density of methanol (CH3OH)(CH3OH) is 0.791 g/mLg/mL. A solution is made by dissolving 24.5 mLmL CH3OHCH3OH in 98.7 mLmL CH3CNCH3CN. |
What is the mole fraction of methanol in the solution?
χCH3OHχCH3OH =
What is the molality of the solution? Assuming CH3OHCH3OH is the solute and CH3CNCH3CN is the solvent.
mCH3OHmCH3OH =
Assuming that the volumes are additive, what is the molarity of CH3OHCH3OH in the solution?
M=
The density of acetonitrile (CH3CN)(CH3CN) is 0.786 g/mLg/mL, and the density of methanol (CH3OH)(CH3OH) is 0.791...
Homework #1 (13) Problem 13.49 The density of acetonitrile (CHCN) is 0.786 g/mL, and the density of methanol (CH-OH) is 0.701 g/mL A solution is made by dissolving 21.5 mL CH,OH in 98.7 mL CH, CN What is the mole fraction of methanol in the solution? Undo riglo Pese keyboard shortcuts Help XCHOR Submit Previous Answers Request Answer X Incorrect: Try Again; 4 attempts remaining Part B What is the molality of the solution? Assuming CH, OH is the solute...
A solution is prepared by dissolving 20.2 mLmL of methanol (CH3OH)(CH3OH) in 100.0 mLmL of water at 25 ∘C∘C. The final volume of the solution is 118 mLmL. The densities of methanol and water at this temperature are 0.782 g/mLg/mL and 1.00 g/mLg/mL, respectively. For this solution, calculate each of the following. a. Molarity b. Molality C. Percent by mass d. Mole Fraction
The density of a 1.96 M solution of LiBr in acetonitrile (CH3CN) in 0.826 g/mL. Calculate the concentration of this solution in (a) molality, (b) mole fraction of LiBr, and (c) mass percent of CH3CN.
A student dissolves 2.5 g of methanol (CH3OH) in 100. mL of a solvent with a density of 1.18 g/mL. The student notices that the volume of the solvent does not change when the methanol dissolves in it. Calculate the molarity and molality of the student's solution. Be sure each of your answer entries has the correct number of significant digits. molarity = 0 molality = 1 x 6 ?
The density of a 2.10 M solution of LiBr in acetonitrile (CH3CN) is 0.826 g/mL. What is the molality (m) of this solution? Note: Assume 1000.0 mL of solution for your calculation. Show your work in the space below and report your answer using the correct units and significant figures.
"calculations only" 1. How would you prepare a 25% m/m NaOH solution in methanol (CH3OH m.m =0.79 g/cm3). 2. How would you prepare a solution of 0.10 mole fraction of glucose (C6H12O6 ) in water? 3. Calculate the molarity and mole fraction of acetone in a 1.00 m solution of acetone (C3H6O) in ethanol (C2H6O). Density of acetone= 0.788 g/mL; Density of ethanol 0.789 g/mL. Assume volumes are additive.
A 500.0±0.2-mL solution was prepared by dissolving 25.00±0.03 mL of methanol (CH3OH, density=0.7914±0.0002 g/mL, molecular mass=32.0419±0.0009 g/mol) in chloroform. Find the molarity ± uncertainty of the methanol.
PROBLEMS: 3 - 2-1 1. (9 points) Aqueous methanol (CH3OH) can be purchased in a solution with a molality that is 1.52 m and the solution has a density of 0.85 g/mL. What is the molarity of the solution? you already have the moles solute with molality density is mass vowme
A solution is prepared by dissolving 20.2 mL of methanol (CH3OH) in 100.0 mL of water at 25 ∘C. The final volume of the solution is 118 mL. The densities of methanol and water at this temperature are 0.782 g/mL and 1.00 g/mL, respectively. For this solution, calculate mole percent M=4.18 m=4.93 percent by mass= 13.6% mole fraction= 8.15*10^-2
concentrated phosphoric acid solution is 85.5% H3PO4 by mass and has a density of 1.69 g/mL at 25°C. What is the molarity of H3PO4? What is the mole fraction of urea, CO(NH2)2, in a solution prepared by dissolving 5.6 g of urea in 30.1 g of methanol, CH3OH? How will an understanding of this concept help you in your healthcare career?